A clump of soft clay is thrown horizontally from an elevation of 7.5 m above the ground with a speed of 19.7 m/s. Where is the clay after 1.54 s? Assume it sticks in place if it hits the ground.
I really don't understand how to answer this question. I've tried to find it by multiplying 19.7m/s*1.54s, but the answer isn't correct. Please help!
