Hi,
I'm really, really stuck with 3 homework questions about logs.
Firstly, you have to find x in terms of a where a>0 and a is not equal 100:
for a^x=10^(2x+1)
and also for 2log(2x)=1+loga
I've just got stuck half way through which makes me think I'm going about these two the wrong way.
The other one is given the simultaneous equations:
2^x=3^y
x+y=1
show that x=log3/log6
Past substituting y from the second equation into the first, I'm a bit stuck.
Many, many thanks and I'd be really grateful for any help,
Matt. Ireland
Bookmarks