I've asked this question already, but i keep getting different answers and I don't know which is right?
A rigid tank is filled part-way with water. After adding the water, the tank contains 15.0 l of air, the temperature is 26°C, and the total pressure inside the tank is 99.7 kPa. If the temperature is lowered to 21°C, what is the new pressure inside the tank? (You may assume that air and water vapor behave as ideal gases, and you may neglect any changes in the volume of the liquid due to thermal expansion.)
The vapor pressure of water is 3.36 kPa at 26°C, and 2.49 kPa at 21°C.
I'm kinda confused on this question. Can someone tell me an explanation on what your doing, step by step until you get your answer. Thanks?
Also I 'm not sure, but do Subtract water vapour pressure at 26 from total pressure to get air pressure, but after that I get confused. Are they not asking for the total pressure inside the tank at 21 °C or are they are asking for air pressure? Then I know you go to Combined Gas Law.