$user_name = "xxxx";
$password = "xxx";
$database = "xxxx";
$server = "localhost";

$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);



$qNum = 'q1';




$SQL = "SELECT * FROM tblquestions WHERE QID = '$qNum'" or die(mysql_error());
$result = mysql_query($SQL);
mysql_close($db_handle);
print "$result";

Its just giving me this error : resource id #4

ive edited the username and password for security reasons