Use the following balanced chemical equation to do your calculations.
Pb(NO3)2 (aq) + 2Kl (aq) -----> PbI2 (s) + 2KNO3 (aq)
How many mg. of Potassium Iodid are required to remove all the lead from a sample of drinking water containing 56.90 mg of lead (II) nitrate?
Please help and show work/explain! I do not understand one bit!
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