The mat of a trampoline is held by 32 springs, each having a spring constant of 5000 N/m. A person with a mass of 40.0 kg jumps from a platform 1.93 m high onto the trampoline. Determine the stretch of each of the springs in cm.
......the answer is 9.72
no idea how they got that
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Thread: physics spring question help?
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03-30-2010, 11:46 PM #1
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physics spring question help?
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10-08-2012, 11:58 PM #2Unregistered
Guest40(9.8)(1.93)=32(1/2)5000x^2 x=0.0972m = 9.72 cm v=1/2kx^2 x=stretch
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